16z^2-24z+9=0

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Solution for 16z^2-24z+9=0 equation: 



16z^2-24z+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{24}{32}=3/4$

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